Raeann, Opal, Lynn and Esther jointly contributed to the cost of a present for their schoolmate. Raeann's contribution is
38 of the total contribution made by the four girls. The ratio of Esther's contribution to the total of Opal's and Lynn's contribution is 3 : 1. What is the total contribution by the four girls if Opal's contribution is
14 of Lynn's contribution and the total amount contributed by Raeann and Esther is $162?
Raeann |
Opal |
Lynn |
Esther |
Total |
3x4 |
5x4 |
8x4 |
|
1x5
|
3x5 |
|
|
1x1 |
4x1 |
|
|
12 u |
1 u |
4 u |
15 u |
32 u |
Working backwards.
Total amount that Opal and Lynn had is the combined repeated identity.
LCM of 1 and 5 = 5
Total amount that Opal, Lynn and Esther had is the next combined repeated identity.
LCM of 5 and 4 = 20
Total amount contributed by Raeann and Esther
= 12 u + 15 u
= 27 u
27 u = 162
1 u = 162 ÷ 27 = $6
Total contribution by the four girls
= 32 u
= 32 x 6
= $192
Answer(s): $192