Mary, Marion, Sabrina and Hazel jointly contributed to the cost of a present for their schoolmate. Mary's contribution is ⁵₆ of the total contribution made by the four girls. The ratio of Hazel's contribution to the total of Marion's and Sabrina's contribution is 2 : 1. What is the total contribution by the four girls if Marion's contribution is ¹₄ of Sabrina's contribution and the total amount contributed by Mary and Hazel is $1530?

Mary	Marion	Sabrina	Hazel	Total
5x15	1x15			6x15
	1x5		2x5
	1x1	4x1
75 u	1 u	4 u	10 u	90 u

Working backwards.

Total amount that Marion and Sabrina had is the combined repeated identity.
LCM of 1 and 5 = 5

Total amount that Marion, Sabrina and Hazel had is the next combined repeated identity.
LCM of 1 and 15 = 15 

Total amount contributed by Mary and Hazel
= 75 u + 10 u
= 85 u

85 u = 1530

1 u = 1530 ÷ 85 = $18

Total contribution by the four girls
= 90 u
= 90 x 18
= $1620

Answer(s): $1620