A philanthropist bought a total of $6060 worth of toys, textbooks and clothes to donate to the needy children. The number of clothes bought was 25% more than the number of toys bought but 25% fewer than the number of textbooks bought. The toy cost $15 each and was $3 more expensive than each textbook but 40% cheaper than each piece of clothes. How many toys and textbooks did the philanthropist donate to the needy children?
Toys |
Clothes |
Textbooks |
4x3 |
1x3 |
|
|
3x1 |
4x1 |
12 u |
3 u |
4 u |
100% + 25% = 125%
125% =
125100 = 1
14 100% - 25% = 75%
75% =
75100 =
34The number of clothes is the repeated identity. Make the number of clothes the same. LCM of 1 and 3 is 3.
Price of each textbook
= 15 - 3
= $12
100% - 40% = 60%
60% of price of toys = $15
1% of the price of toys =
1560 100% of the price of toys =
1560 x 100 = $25
Price of each piece of clothes = $25
|
Toys |
Clothes |
Textbooks |
Number |
12 u |
3 u |
4 u |
Value |
15 |
25 |
12 |
Total value |
180 u |
75 u |
48 u |
Total amount spent
= 4 u x 12 + 12 u x 15 + 3 u x 25
= 48 u + 180 u + 75 u
= 303 u
303 u = 6060
1 u = 6060 ÷ 303 = 20
Number of toys and textbooks
= 25 u + 4 u
= 29 u
= 29 x 20
= 580
Answer(s): 580