A philanthropist bought a total of $8510 worth of toys, textbooks and clothes to donate to the needy children. The number of clothes bought was 20% more than the number of toys bought but 20% fewer than the number of textbooks bought. The toy cost $12 each and was $2 more expensive than each textbook but 40% cheaper than each piece of clothes. How many toys and textbooks did the philanthropist donate to the needy children?
Toys |
Clothes |
Textbooks |
5x4 |
1x4 |
|
|
4x1 |
5x1 |
20 u |
4 u |
5 u |
100% + 20% = 120%
120% =
120100 = 1
15 100% - 20% = 80%
80% =
80100 =
45The number of clothes is the repeated identity. Make the number of clothes the same. LCM of 1 and 4 is 4.
Price of each textbook
= 12 - 2
= $10
100% - 40% = 60%
60% of price of toys = $12
1% of the price of toys =
1260 100% of the price of toys =
1260 x 100 = $20
Price of each piece of clothes = $20
|
Toys |
Clothes |
Textbooks |
Number |
20 u |
4 u |
5 u |
Value |
12 |
20 |
10 |
Total value |
240 u |
80 u |
50 u |
Total amount spent
= 5 u x 10 + 20 u x 12 + 4 u x 20
= 50 u + 240 u + 80 u
= 370 u
370 u = 8510
1 u = 8510 ÷ 370 = 23
Number of toys and textbooks
= 20 u + 5 u
= 25 u
= 25 x 23
= 575
Answer(s): 575