A philanthropist bought a total of $35190 worth of toys, textbooks and clothes to donate to the needy children. The number of clothes bought was 30% more than the number of toys bought but 30% fewer than the number of textbooks bought. The toy cost $12 each and was $3 more expensive than each textbook but 40% cheaper than each piece of clothes. How many toys and textbooks did the philanthropist donate to the needy children?
Toys |
Clothes |
Textbooks |
10x7 |
3x7 |
|
|
7x3 |
10x3 |
70 u |
21 u |
30 u |
100% + 30% = 130%
130% =
130100 = 1
310 100% - 30% = 70%
70% =
70100 =
710The number of clothes is the repeated identity. Make the number of clothes the same. LCM of 3 and 7 is 21.
Price of each textbook
= 12 - 3
= $9
100% - 40% = 60%
60% of price of toys = $12
1% of the price of toys =
1260 100% of the price of toys =
1260 x 100 = $20
Price of each piece of clothes = $20
|
Toys |
Clothes |
Textbooks |
Number |
70 u |
21 u |
30 u |
Value |
12 |
20 |
9 |
Total value |
840 u |
420 u |
270 u |
Total amount spent
= 30 u x 9 + 70 u x 12 + 21 u x 20
= 270 u + 840 u + 420 u
= 1530 u
1530 u = 35190
1 u = 35190 ÷ 1530 = 23
Number of toys and textbooks
= 30 u + 30 u
= 60 u
= 60 x 23
= 1380
Answer(s): 1380