A philanthropist bought a total of $9000 worth of toys, textbooks and clothes to donate to the needy children. The number of clothes bought was 20% more than the number of toys bought but 20% fewer than the number of textbooks bought. The toy cost $15 each and was $5 more expensive than each textbook but 40% cheaper than each piece of clothes. How many toys and textbooks did the philanthropist donate to the needy children?
Toys |
Clothes |
Textbooks |
5x4 |
1x4 |
|
|
4x1 |
5x1 |
20 u |
4 u |
5 u |
100% + 20% = 120%
120% =
120100 = 1
15 100% - 20% = 80%
80% =
80100 =
45The number of clothes is the repeated identity. Make the number of clothes the same. LCM of 1 and 4 is 4.
Price of each textbook
= 15 - 5
= $10
100% - 40% = 60%
60% of price of toys = $15
1% of the price of toys =
1560 100% of the price of toys =
1560 x 100 = $25
Price of each piece of clothes = $25
|
Toys |
Clothes |
Textbooks |
Number |
20 u |
4 u |
5 u |
Value |
15 |
25 |
10 |
Total value |
300 u |
100 u |
50 u |
Total amount spent
= 5 u x 10 + 20 u x 15 + 4 u x 25
= 50 u + 300 u + 100 u
= 450 u
450 u = 9000
1 u = 9000 ÷ 450 = 20
Number of toys and textbooks
= 20 u + 5 u
= 25 u
= 25 x 20
= 500
Answer(s): 500