A philanthropist bought a total of $60060 worth of toys, textbooks and clothes to donate to the needy children. The number of clothes bought was 30% more than the number of toys bought but 30% fewer than the number of textbooks bought. The toy cost $18 each and was $4 more expensive than each textbook but 40% cheaper than each piece of clothes. How many toys and textbooks did the philanthropist donate to the needy children?
Toys |
Clothes |
Textbooks |
10x7 |
3x7 |
|
|
7x3 |
10x3 |
70 u |
21 u |
30 u |
100% + 30% = 130%
130% =
130100 = 1
310 100% - 30% = 70%
70% =
70100 =
710The number of clothes is the repeated identity. Make the number of clothes the same. LCM of 3 and 7 is 21.
Price of each textbook
= 18 - 4
= $14
100% - 40% = 60%
60% of price of toys = $18
1% of the price of toys =
1860 100% of the price of toys =
1860 x 100 = $30
Price of each piece of clothes = $30
|
Toys |
Clothes |
Textbooks |
Number |
70 u |
21 u |
30 u |
Value |
18 |
30 |
14 |
Total value |
1260 u |
630 u |
420 u |
Total amount spent
= 30 u x 14 + 70 u x 18 + 21 u x 30
= 420 u + 1260 u + 630 u
= 2310 u
2310 u = 60060
1 u = 60060 ÷ 2310 = 26
Number of toys and textbooks
= 30 u + 30 u
= 60 u
= 60 x 26
= 1560
Answer(s): 1560