A philanthropist bought a total of $6032 worth of toys, textbooks and clothes to donate to the needy children. The number of clothes bought was 25% more than the number of toys bought but 25% fewer than the number of textbooks bought. The toy cost $12 each and was $5 more expensive than each textbook but 40% cheaper than each piece of clothes. How many toys and textbooks did the philanthropist donate to the needy children?
Toys |
Clothes |
Textbooks |
4x3 |
1x3 |
|
|
3x1 |
4x1 |
12 u |
3 u |
4 u |
100% + 25% = 125%
125% =
125100 = 1
14 100% - 25% = 75%
75% =
75100 =
34The number of clothes is the repeated identity. Make the number of clothes the same. LCM of 1 and 3 is 3.
Price of each textbook
= 12 - 5
= $7
100% - 40% = 60%
60% of price of toys = $12
1% of the price of toys =
1260 100% of the price of toys =
1260 x 100 = $20
Price of each piece of clothes = $20
|
Toys |
Clothes |
Textbooks |
Number |
12 u |
3 u |
4 u |
Value |
12 |
20 |
7 |
Total value |
144 u |
60 u |
28 u |
Total amount spent
= 4 u x 7 + 12 u x 12 + 3 u x 20
= 28 u + 144 u + 60 u
= 232 u
232 u = 6032
1 u = 6032 ÷ 232 = 26
Number of toys and textbooks
= 25 u + 4 u
= 29 u
= 29 x 26
= 754
Answer(s): 754