A philanthropist bought a total of $47625 worth of toys, textbooks and clothes to donate to the needy children. The number of clothes bought was 30% more than the number of toys bought but 30% fewer than the number of textbooks bought. The toy cost $15 each and was $4 more expensive than each textbook but 40% cheaper than each piece of clothes. How many toys and textbooks did the philanthropist donate to the needy children?
Toys |
Clothes |
Textbooks |
10x7 |
3x7 |
|
|
7x3 |
10x3 |
70 u |
21 u |
30 u |
100% + 30% = 130%
130% =
130100 = 1
310 100% - 30% = 70%
70% =
70100 =
710The number of clothes is the repeated identity. Make the number of clothes the same. LCM of 3 and 7 is 21.
Price of each textbook
= 15 - 4
= $11
100% - 40% = 60%
60% of price of toys = $15
1% of the price of toys =
1560 100% of the price of toys =
1560 x 100 = $25
Price of each piece of clothes = $25
|
Toys |
Clothes |
Textbooks |
Number |
70 u |
21 u |
30 u |
Value |
15 |
25 |
11 |
Total value |
1050 u |
525 u |
330 u |
Total amount spent
= 30 u x 11 + 70 u x 15 + 21 u x 25
= 330 u + 1050 u + 525 u
= 1905 u
1905 u = 47625
1 u = 47625 ÷ 1905 = 25
Number of toys and textbooks
= 30 u + 30 u
= 60 u
= 60 x 25
= 1500
Answer(s): 1500