In a shop, 60% of the number of vegetables sold were beets and the rest were carrots. Each beet cost 50¢ and each carrot cost 10¢ less than the cost of each beet. Given that $269.10 was collected from the sale of the vegetables,
- How many beets were sold?
- How much was collected from the sale of the carrots only?
(a)
|
Beets |
Carrots |
Number |
3 u |
2 u |
Value |
$0.50 |
$0.4 |
Total value |
1.5 u |
0.8 u |
60% =
60100 =
35Cost of each carrot
= 0.50 - 0.10
= $0.4
Total cost of the vegetables
= 1.5 u + 0.8 u
= 2.3 u
2.3 u = 269.10
1 u = 269.10 ÷ 2.3 = 117
Number of beets sold
= 3 u
= 3 x 117
= $351
(b)
Amount collected from the sale of carrots
= 0.8 u
= 0.8 x 117
= $93.60
Answer(s): (a) 351; (b) $93.60