In a kiosk, 60% of the number of vegetables sold were yams and the rest were beets. Each yam cost 25¢ and each beet cost 10¢ less than the cost of each yam. Given that $207.90 was collected from the sale of the vegetables,
- How many yams were sold?
- How much was collected from the sale of the beets only?
(a)
|
Yams |
Beets |
Number |
3 u |
2 u |
Value |
$0.25 |
$0.15 |
Total value |
0.75 u |
0.3 u |
60% =
60100 =
35Cost of each beet
= 0.25 - 0.10
= $0.15
Total cost of the vegetables
= 0.75 u + 0.3 u
= 1.05 u
1.05 u = 207.90
1 u = 207.90 ÷ 1.05 = 198
Number of yams sold
= 3 u
= 3 x 198
= $594
(b)
Amount collected from the sale of beets
= 0.3 u
= 0.3 x 198
= $59.40
Answer(s): (a) 594; (b) $59.40