In a shop, 60% of the number of vegetables sold were garlics and the rest were potatoes. Each garlic cost 50¢ and each potato cost 10¢ less than the cost of each garlic. Given that $241.50 was collected from the sale of the vegetables,
- How many garlics were sold?
- How much was collected from the sale of the potatoes only?
(a)
|
Garlics |
Potatoes |
Number |
3 u |
2 u |
Value |
$0.50 |
$0.4 |
Total value |
1.5 u |
0.8 u |
60% =
60100 =
35Cost of each potato
= 0.50 - 0.10
= $0.4
Total cost of the vegetables
= 1.5 u + 0.8 u
= 2.3 u
2.3 u = 241.50
1 u = 241.50 ÷ 2.3 = 105
Number of garlics sold
= 3 u
= 3 x 105
= $315
(b)
Amount collected from the sale of potatoes
= 0.8 u
= 0.8 x 105
= $84.00
Answer(s): (a) 315; (b) $84.00