In a shop, 60% of the number of vegetables sold were garlics and the rest were sweet potatoes. Each garlic cost 25¢ and each sweet potato cost 10¢ less than the cost of each garlic. Given that $228.90 was collected from the sale of the vegetables,
- How many garlics were sold?
- How much was collected from the sale of the sweet potatoes only?
(a)
|
Garlics |
Sweet Potatoes |
Number |
3 u |
2 u |
Value |
$0.25 |
$0.15 |
Total value |
0.75 u |
0.3 u |
60% =
60100 =
35Cost of each sweet potato
= 0.25 - 0.10
= $0.15
Total cost of the vegetables
= 0.75 u + 0.3 u
= 1.05 u
1.05 u = 228.90
1 u = 228.90 ÷ 1.05 = 218
Number of garlics sold
= 3 u
= 3 x 218
= $654
(b)
Amount collected from the sale of sweet potatoes
= 0.3 u
= 0.3 x 218
= $65.40
Answer(s): (a) 654; (b) $65.40