In a supermarket, 60% of the number of vegetables sold were ginger and the rest were potatoes. Each ginger cost 25¢ and each potato cost 10¢ less than the cost of each ginger. Given that $247.80 was collected from the sale of the vegetables,
- How many ginger were sold?
- How much was collected from the sale of the potatoes only?
(a)
|
Ginger |
Potatoes |
Number |
3 u |
2 u |
Value |
$0.25 |
$0.15 |
Total value |
0.75 u |
0.3 u |
60% =
60100 =
35Cost of each potato
= 0.25 - 0.10
= $0.15
Total cost of the vegetables
= 0.75 u + 0.3 u
= 1.05 u
1.05 u = 247.80
1 u = 247.80 ÷ 1.05 = 236
Number of ginger sold
= 3 u
= 3 x 236
= $708
(b)
Amount collected from the sale of potatoes
= 0.3 u
= 0.3 x 236
= $70.80
Answer(s): (a) 708; (b) $70.80