In a supermarket, 60% of the number of vegetables sold were potatoes and the rest were onions. Each potato cost 25¢ and each onion cost 10¢ less than the cost of each potato. Given that $233.10 was collected from the sale of the vegetables,
- How many potatoes were sold?
- How much was collected from the sale of the onions only?
(a)
|
Potatoes |
Onions |
Number |
3 u |
2 u |
Value |
$0.25 |
$0.15 |
Total value |
0.75 u |
0.3 u |
60% =
60100 =
35Cost of each onion
= 0.25 - 0.10
= $0.15
Total cost of the vegetables
= 0.75 u + 0.3 u
= 1.05 u
1.05 u = 233.10
1 u = 233.10 ÷ 1.05 = 222
Number of potatoes sold
= 3 u
= 3 x 222
= $666
(b)
Amount collected from the sale of onions
= 0.3 u
= 0.3 x 222
= $66.60
Answer(s): (a) 666; (b) $66.60