In a kiosk, 60% of the number of vegetables sold were potatoes and the rest were ginger. Each potato cost 25¢ and each ginger cost 20¢ less than the cost of each potato. Given that $246.50 was collected from the sale of the vegetables,
- How many potatoes were sold?
- How much was collected from the sale of the ginger only?
(a)
|
Potatoes |
Ginger |
Number |
3 u |
2 u |
Value |
$0.25 |
$0.05 |
Total value |
0.75 u |
0.1 u |
60% =
60100 =
35Cost of each ginger
= 0.25 - 0.20
= $0.05
Total cost of the vegetables
= 0.75 u + 0.1 u
= 0.85 u
0.85 u = 246.50
1 u = 246.50 ÷ 0.85 = 290
Number of potatoes sold
= 3 u
= 3 x 290
= $870
(b)
Amount collected from the sale of ginger
= 0.1 u
= 0.1 x 290
= $29.00
Answer(s): (a) 870; (b) $29.00