In a kiosk, 60% of the number of vegetables sold were potatoes and the rest were beets. Each potato cost 50¢ and each beet cost 20¢ less than the cost of each potato. Given that $233.10 was collected from the sale of the vegetables,
- How many potatoes were sold?
- How much was collected from the sale of the beets only?
(a)
|
Potatoes |
Beets |
Number |
3 u |
2 u |
Value |
$0.50 |
$0.3 |
Total value |
1.5 u |
0.6 u |
60% =
60100 =
35Cost of each beet
= 0.50 - 0.20
= $0.3
Total cost of the vegetables
= 1.5 u + 0.6 u
= 2.1 u
2.1 u = 233.10
1 u = 233.10 ÷ 2.1 = 111
Number of potatoes sold
= 3 u
= 3 x 111
= $333
(b)
Amount collected from the sale of beets
= 0.6 u
= 0.6 x 111
= $66.60
Answer(s): (a) 333; (b) $66.60