Marion, Hilda and Tina shared $550 among themselves. Hilda and Tina shared ²₅ of the money equally. After Hilda gave away some of her money to Marion, Tina had 5 times as much money as Hilda. How much money did Hilda give to Marion?

	Hilda	Tina	Marion	Total
Before	1x5 = 5 u	1x5 = 5 u	3x5 = 15 u	25 u
Change	- 4 u	No change	+ 4 u
After	1x1 = 1 u	5x1 = 5 u	19 u	25 u

Hilda and Tina shared ²₅ of the money equally.

Fraction of the money that Hilda and Tina each had
= ²₅ ÷ 2
= ²₅ x ¹₂
= ¹₅

The amount that Tina had remains unchanged.  The amount that Tina had is the unchanged quantity. Make the amount that Tina had the same. LCM of 1 and 5 is 5.

The amount that Hilda and Tina had at first is the same.

Total amount that they had at first
= 5 u + 5 u + 15 u
= 25 u

25 u = 550

1 u = 550 ÷ 25 = 22

Amount that Hilda gave to Marion
= 5 u - 1 u
= 4 u
= 4 x 22
= $88

Answer(s): $88