Raeann had 45 as many coins as Fanny. The sum of the number of coins Raeann and Fanny had was the same as the number of coins that Min had. After trading, Min gave 10% of her coins to Raeann and received 40% of Fanny's coins. After that, Fanny continued to trade and increased her number of coins in the end by 10%, find the ratio of her number of coins to the sum of Raeann's and Min's coins in the end.
| |
Raeann |
Min |
Fanny |
Total |
| Before |
4 u |
9 u |
5 u |
18 u |
| Change 1 |
+ 0.9 u |
- 0.9 u |
|
|
| Change 2 |
|
+ 2 u |
- 2 u |
|
| After 1 |
4.9 u |
10.1 u |
3 u |
|
| Change 3 |
- 0.3 u |
+ 0.3 u |
|
| After 2 |
14.7 u |
3.3 u |
18 u |
Total number of coins that Raeann and Fanny had at first
= 4 u + 5 u
= 9 u
Number of coins that Min had at first = 9 u
Number of coins that Min gave to Raeann
= 10% x 9 u
=
10100 x 4 u
= 0.9 u
Number of coins that Min received from Fanny
= 40% x 5 u
=
40100 x 5 u
= 2 u
Number of coins that Fanny increased by when she continued to trade
= 10% x 3 u
=
10100 x 3 u
= 0.3 u
Number of coins that Raeann and Min had in the end
= 4.9 u + 10.1 u - 0.3 u
= 14.7 u
In the end
Fanny : Raeann and Min
3.3 : 14.7
330 : 1470
11 : 49
Answer(s): 11 : 49
