Riordan, Tommy and Wesley shared a sum of money. The amount received by Tommy was
45 the amount of money received by Wesley. After Riordan had given $44 to Tommy and $25 to Wesley, Tommy gave $2 to Wesley. In the end, 3 of them had the same amount of money. Find the difference between the amount of money that Riordan and Tommy had at first.
|
Riordan |
Tommy |
Wesley |
Before |
4 u + 111 |
4 u |
5 u |
Change 1 |
- 44 |
+ 44 |
|
Change 2 |
- 25 |
|
+ 25 |
Change 3 |
|
- 2 |
+ 2 |
After |
4 u + 42 |
4 u + 42 |
5 u + 27 |
Amount that Tommy had in the end = 4 u + 42
Amount that Wesley had in the end = 5 u + 27
Amount that Riordan had at first
= 4 u + 42 + 44 + 25
= 4 u + 111
Amount that Tommy and Wesley had in the end is the same.
4 u + 42 = 5 u + 27
5 u - 4 u = 42 - 27
1 u = 15
Amount that Riordan and Tommy had in the end is the same.
Amount that Riordan had in the end
= 4 u + 42
= 4 x 15 + 42
= 60 + 42
= $102
Amount that Riordan had at first
= 102 + 44 + 25
= $171
Difference in the amounts between Riordan and Tommy at first
= 171 - 60
= $111
Answer(s): $111