Pierre, Tommy and Michael shared a sum of money. The amount received by Tommy was
34 the amount of money received by Michael. After Pierre had given $55 to Tommy and $23 to Michael, Tommy gave $8 to Michael. In the end, 3 of them had the same amount of money. Find the difference between the amount of money that Pierre and Tommy had at first.
|
Pierre |
Tommy |
Michael |
Before |
3 u + 125 |
3 u |
4 u |
Change 1 |
- 55 |
+ 55 |
|
Change 2 |
- 23 |
|
+ 23 |
Change 3 |
|
- 8 |
+ 8 |
After |
3 u + 47 |
3 u + 47 |
4 u + 31 |
Amount that Tommy had in the end = 3 u + 47
Amount that Michael had in the end = 4 u + 31
Amount that Pierre had at first
= 3 u + 47 + 55 + 23
= 3 u + 125
Amount that Tommy and Michael had in the end is the same.
3 u + 47 = 4 u + 31
4 u - 3 u = 47 - 31
1 u = 16
Amount that Pierre and Tommy had in the end is the same.
Amount that Pierre had in the end
= 3 u + 47
= 3 x 16 + 47
= 48 + 47
= $95
Amount that Pierre had at first
= 95 + 55 + 23
= $173
Difference in the amounts between Pierre and Tommy at first
= 173 - 48
= $125
Answer(s): $125