Zane, Gabriel and Ahmad shared a sum of money. The amount received by Gabriel was
56 the amount of money received by Ahmad. After Zane had given $44 to Gabriel and $21 to Ahmad, Gabriel gave $5 to Ahmad. In the end, 3 of them had the same amount of money. Find the difference between the amount of money that Zane and Gabriel had at first.
|
Zane |
Gabriel |
Ahmad |
Before |
5 u + 104 |
5 u |
6 u |
Change 1 |
- 44 |
+ 44 |
|
Change 2 |
- 21 |
|
+ 21 |
Change 3 |
|
- 5 |
+ 5 |
After |
5 u + 39 |
5 u + 39 |
6 u + 26 |
Amount that Gabriel had in the end = 5 u + 39
Amount that Ahmad had in the end = 6 u + 26
Amount that Zane had at first
= 5 u + 39 + 44 + 21
= 5 u + 104
Amount that Gabriel and Ahmad had in the end is the same.
5 u + 39 = 6 u + 26
6 u - 5 u = 39 - 26
1 u = 13
Amount that Zane and Gabriel had in the end is the same.
Amount that Zane had in the end
= 5 u + 39
= 5 x 13 + 39
= 65 + 39
= $104
Amount that Zane had at first
= 104 + 44 + 21
= $169
Difference in the amounts between Zane and Gabriel at first
= 169 - 65
= $104
Answer(s): $104