Pierre, Albert and Elijah shared a sum of money. The amount received by Albert was ²₃ the amount of money received by Elijah. After Pierre had given $51 to Albert and $29 to Elijah, Albert gave $7 to Elijah. In the end, 3 of them had the same amount of money. Find the difference between the amount of money that Pierre and Albert had at first.

	Pierre	Albert	Elijah
Before	2 u + 124	2 u	3 u
Change 1	- 51	+ 51
Change 2	- 29		+ 29
Change 3		- 7	+ 7
After	2 u + 44	2 u + 44	3 u + 36

Amount that Albert had in the end = 2 u + 44 

Amount that Elijah had in the end = 3 u + 36

Amount that Pierre had at first 
= 2 u + 44 + 51 + 29
= 2 u + 124

Amount that Albert and Elijah had in the end is the same.

2 u + 44 = 3 u + 36
3 u - 2 u = 44 - 36

1 u = 8

Amount that Pierre and Albert had in the end is the same.

Amount that Pierre had in the end
= 2 u + 44
= 2 x 8 + 44
= 16 + 44
= $60

Amount that Pierre had at first
= 60 + 51 + 29
= $140

Difference in the amounts between Pierre and Albert at first
= 140 - 16
= $124

Answer(s): $124