70% of the mini cupcakes in Packet Y were cheese mini cupcakes and the rest were blueberry mini cupcakes. Packet Z had 25% more cheese mini cupcakes than Packet Y and four times as many mini cupcakes than the total number of mini cupcakes in Packet Y. Find the percentage of the blueberry mini cupcakes in Packet Z that would need to be transferred into Packet Y, so that there were an equal number of cheese and blueberry mini cupcakes in Packet Y.
|
Packet Y |
Packet Z |
|
Cheese |
Blueberry |
Cheese |
Blueberry |
|
10 u |
40 u |
Before |
7 u |
3 u |
8.75 u |
31.25 u |
Change |
|
+ 4 u |
|
- 4 u |
After |
7 u |
7 u |
8.75 u |
27.25 u |
70% =
70100 =
710 100 %+ 25% = 125%
Total number of mini cupcakes in Packet Y
= 7 u + 3 u
= 10 u
Total number of mini cupcakes in Packet Z
= 4 x 10 u
= 40 u
Number of cheese mini cupcakes in Packet Z
= 125% x 7 u
=
125100 x 7 u
= 8.75 u
Number of cheese mini cupcakes in Packet Z
= 40 u - 8.75 u
= 31.25 u
Number of blueberry mini cupcakes to be transferred from Packet Z to Packet Y
= 7 u - 3 u
= 4 u
Percentage of mini cupcakes to be transferred from Packet Z
=
431.25 x 100%
= 12.8%
Answer(s): 12.8%