80% of the mochi balls in Packet N were strawberry mochi balls and the rest were banana mochi balls. Packet P had 30% more strawberry mochi balls than Packet N and twice as many mochi balls than the total number of mochi balls in Packet N. Find the percentage of the banana mochi balls in Packet P that would need to be transferred into Packet N, so that there were an equal number of strawberry and banana mochi balls in Packet N.
|
Packet N |
Packet P |
|
Strawberry |
Banana |
Strawberry |
Banana |
|
5 u |
10 u |
Before |
4 u |
1 u |
5.2 u |
4.8 u |
Change |
|
+ 3 u |
|
- 3 u |
After |
4 u |
4 u |
5.2 u |
1.8 u |
80% =
80100 =
45 100 %+ 30% = 130%
Total number of mochi balls in Packet N
= 4 u + 1 u
= 5 u
Total number of mochi balls in Packet P
= 2 x 5 u
= 10 u
Number of strawberry mochi balls in Packet P
= 130% x 4 u
=
130100 x 4 u
= 5.2 u
Number of strawberry mochi balls in Packet P
= 10 u - 5.2 u
= 4.8 u
Number of banana mochi balls to be transferred from Packet P to Packet N
= 4 u - 1 u
= 3 u
Percentage of mochi balls to be transferred from Packet P
=
34.8 x 100%
= 62.5%
Answer(s): 62.5%