80% of the candies in Packet T were chocolate chip candies and the rest were strawberry candies. Packet U had 30% more chocolate chip candies than Packet T and twice as many candies than the total number of candies in Packet T. Find the percentage of the strawberry candies in Packet U that would need to be transferred into Packet T, so that there were an equal number of chocolate chip and strawberry candies in Packet T.

	Packet T		Packet U
	Chocolate Chip	Strawberry	Chocolate Chip	Strawberry
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of candies in Packet T
= 4 u + 1 u
= 5 u

Total number of candies in Packet U
= 2 x 5 u 
= 10 u

Number of chocolate chip candies in Packet U
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of chocolate chip candies in Packet U
= 10 u - 5.2 u
= 4.8 u

Number of strawberry candies to be transferred from Packet U to Packet T
= 4 u - 1 u
= 3 u

Percentage of candies to be transferred from Packet U
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%