80% of the caramel apples in Packet V were cheese caramel apples and the rest were vanilla caramel apples. Packet W had 30% more cheese caramel apples than Packet V and twice as many caramel apples than the total number of caramel apples in Packet V. Find the percentage of the vanilla caramel apples in Packet W that would need to be transferred into Packet V, so that there were an equal number of cheese and vanilla caramel apples in Packet V.

	Packet V		Packet W
	Cheese	Vanilla	Cheese	Vanilla
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of caramel apples in Packet V
= 4 u + 1 u
= 5 u

Total number of caramel apples in Packet W
= 2 x 5 u 
= 10 u

Number of cheese caramel apples in Packet W
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of cheese caramel apples in Packet W
= 10 u - 5.2 u
= 4.8 u

Number of vanilla caramel apples to be transferred from Packet W to Packet V
= 4 u - 1 u
= 3 u

Percentage of caramel apples to be transferred from Packet W
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%