70% of the caramel apples in Packet Q were cranberry caramel apples and the rest were banana caramel apples. Packet R had 25% more cranberry caramel apples than Packet Q and four times as many caramel apples than the total number of caramel apples in Packet Q. Find the percentage of the banana caramel apples in Packet R that would need to be transferred into Packet Q, so that there were an equal number of cranberry and banana caramel apples in Packet Q.

	Packet Q		Packet R
	Cranberry	Banana	Cranberry	Banana
	10 u		40 u
Before	7 u	3 u	8.75 u	31.25 u
Change		+ 4 u		- 4 u
After	7 u	7 u	8.75 u	27.25 u

70% = ⁷⁰₁₀₀ = ⁷₁₀
100 %+ 25% = 125%

 Total number of caramel apples in Packet Q
= 7 u + 3 u
= 10 u

Total number of caramel apples in Packet R
= 4 x 10 u 
= 40 u

Number of cranberry caramel apples in Packet R
= 125% x 7 u
=  ¹²⁵₁₀₀ x 7 u
= 8.75 u

Number of cranberry caramel apples in Packet R
= 40 u - 8.75 u
= 31.25 u

Number of banana caramel apples to be transferred from Packet R to Packet Q
= 7 u - 3 u
= 4 u

Percentage of caramel apples to be transferred from Packet R
= ⁴_31.25 x 100%
= 12.8%

Answer(s): 12.8%