80% of the candies in Packet F were strawberry candies and the rest were blueberry candies. Packet G had 30% more strawberry candies than Packet F and twice as many candies than the total number of candies in Packet F. Find the percentage of the blueberry candies in Packet G that would need to be transferred into Packet F, so that there were an equal number of strawberry and blueberry candies in Packet F.

	Packet F		Packet G
	Strawberry	Blueberry	Strawberry	Blueberry
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of candies in Packet F
= 4 u + 1 u
= 5 u

Total number of candies in Packet G
= 2 x 5 u 
= 10 u

Number of strawberry candies in Packet G
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of strawberry candies in Packet G
= 10 u - 5.2 u
= 4.8 u

Number of blueberry candies to be transferred from Packet G to Packet F
= 4 u - 1 u
= 3 u

Percentage of candies to be transferred from Packet G
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%