60% of the turkish delights in Packet M were chocolate chip turkish delights and the rest were cherry turkish delights. Packet N had 25% more chocolate chip turkish delights than Packet M and twice as many turkish delights than the total number of turkish delights in Packet M. Find the percentage of the cherry turkish delights in Packet N that would need to be transferred into Packet M, so that there were an equal number of chocolate chip and cherry turkish delights in Packet M.
|
Packet M |
Packet N |
|
Chocolate Chip |
Cherry |
Chocolate Chip |
Cherry |
|
5 u |
10 u |
Before |
3 u |
2 u |
3.75 u |
6.25 u |
Change |
|
+ 1 u |
|
- 1 u |
After |
3 u |
3 u |
3.75 u |
5.25 u |
60% =
60100 =
35 100 %+ 25% = 125%
Total number of turkish delights in Packet M
= 3 u + 2 u
= 5 u
Total number of turkish delights in Packet N
= 2 x 5 u
= 10 u
Number of chocolate chip turkish delights in Packet N
= 125% x 3 u
=
125100 x 3 u
= 3.75 u
Number of chocolate chip turkish delights in Packet N
= 10 u - 3.75 u
= 6.25 u
Number of cherry turkish delights to be transferred from Packet N to Packet M
= 3 u - 2 u
= 1 u
Percentage of turkish delights to be transferred from Packet N
=
16.25 x 100%
= 16%
Answer(s): 16%