60% of the caramel apples in Packet B were apple caramel apples and the rest were blueberry caramel apples. Packet C had 25% more apple caramel apples than Packet B and twice as many caramel apples than the total number of caramel apples in Packet B. Find the percentage of the blueberry caramel apples in Packet C that would need to be transferred into Packet B, so that there were an equal number of apple and blueberry caramel apples in Packet B.

	Packet B		Packet C
	Apple	Blueberry	Apple	Blueberry
	5 u		10 u
Before	3 u	2 u	3.75 u	6.25 u
Change		+ 1 u		- 1 u
After	3 u	3 u	3.75 u	5.25 u

60% = ⁶⁰₁₀₀ = ³₅
100 %+ 25% = 125%

 Total number of caramel apples in Packet B
= 3 u + 2 u
= 5 u

Total number of caramel apples in Packet C
= 2 x 5 u 
= 10 u

Number of apple caramel apples in Packet C
= 125% x 3 u
=  ¹²⁵₁₀₀ x 3 u
= 3.75 u

Number of apple caramel apples in Packet C
= 10 u - 3.75 u
= 6.25 u

Number of blueberry caramel apples to be transferred from Packet C to Packet B
= 3 u - 2 u
= 1 u

Percentage of caramel apples to be transferred from Packet C
= ¹_6.25 x 100%
= 16%

Answer(s): 16%