80% of the mini cupcakes in Packet M were cheese mini cupcakes and the rest were banana mini cupcakes. Packet N had 30% more cheese mini cupcakes than Packet M and twice as many mini cupcakes than the total number of mini cupcakes in Packet M. Find the percentage of the banana mini cupcakes in Packet N that would need to be transferred into Packet M, so that there were an equal number of cheese and banana mini cupcakes in Packet M.
|
Packet M |
Packet N |
|
Cheese |
Banana |
Cheese |
Banana |
|
5 u |
10 u |
Before |
4 u |
1 u |
5.2 u |
4.8 u |
Change |
|
+ 3 u |
|
- 3 u |
After |
4 u |
4 u |
5.2 u |
1.8 u |
80% =
80100 =
45 100 %+ 30% = 130%
Total number of mini cupcakes in Packet M
= 4 u + 1 u
= 5 u
Total number of mini cupcakes in Packet N
= 2 x 5 u
= 10 u
Number of cheese mini cupcakes in Packet N
= 130% x 4 u
=
130100 x 4 u
= 5.2 u
Number of cheese mini cupcakes in Packet N
= 10 u - 5.2 u
= 4.8 u
Number of banana mini cupcakes to be transferred from Packet N to Packet M
= 4 u - 1 u
= 3 u
Percentage of mini cupcakes to be transferred from Packet N
=
34.8 x 100%
= 62.5%
Answer(s): 62.5%