60% of the turkish delights in Packet X were cherry turkish delights and the rest were cheese turkish delights. Packet Y had 25% more cherry turkish delights than Packet X and twice as many turkish delights than the total number of turkish delights in Packet X. Find the percentage of the cheese turkish delights in Packet Y that would need to be transferred into Packet X, so that there were an equal number of cherry and cheese turkish delights in Packet X.
|
Packet X |
Packet Y |
|
Cherry |
Cheese |
Cherry |
Cheese |
|
5 u |
10 u |
Before |
3 u |
2 u |
3.75 u |
6.25 u |
Change |
|
+ 1 u |
|
- 1 u |
After |
3 u |
3 u |
3.75 u |
5.25 u |
60% =
60100 =
35 100 %+ 25% = 125%
Total number of turkish delights in Packet X
= 3 u + 2 u
= 5 u
Total number of turkish delights in Packet Y
= 2 x 5 u
= 10 u
Number of cherry turkish delights in Packet Y
= 125% x 3 u
=
125100 x 3 u
= 3.75 u
Number of cherry turkish delights in Packet Y
= 10 u - 3.75 u
= 6.25 u
Number of cheese turkish delights to be transferred from Packet Y to Packet X
= 3 u - 2 u
= 1 u
Percentage of turkish delights to be transferred from Packet Y
=
16.25 x 100%
= 16%
Answer(s): 16%