60% of the sweets in Packet J were strawberry sweets and the rest were chocolate chip sweets. Packet K had 25% more strawberry sweets than Packet J and twice as many sweets than the total number of sweets in Packet J. Find the percentage of the chocolate chip sweets in Packet K that would need to be transferred into Packet J, so that there were an equal number of strawberry and chocolate chip sweets in Packet J.

	Packet J		Packet K
	Strawberry	Chocolate Chip	Strawberry	Chocolate Chip
	5 u		10 u
Before	3 u	2 u	3.75 u	6.25 u
Change		+ 1 u		- 1 u
After	3 u	3 u	3.75 u	5.25 u

60% = ⁶⁰₁₀₀ = ³₅
100 %+ 25% = 125%

 Total number of sweets in Packet J
= 3 u + 2 u
= 5 u

Total number of sweets in Packet K
= 2 x 5 u 
= 10 u

Number of strawberry sweets in Packet K
= 125% x 3 u
=  ¹²⁵₁₀₀ x 3 u
= 3.75 u

Number of strawberry sweets in Packet K
= 10 u - 3.75 u
= 6.25 u

Number of chocolate chip sweets to be transferred from Packet K to Packet J
= 3 u - 2 u
= 1 u

Percentage of sweets to be transferred from Packet K
= ¹_6.25 x 100%
= 16%

Answer(s): 16%