80% of the candies in Packet J were apple candies and the rest were cheese candies. Packet K had 30% more apple candies than Packet J and twice as many candies than the total number of candies in Packet J. Find the percentage of the cheese candies in Packet K that would need to be transferred into Packet J, so that there were an equal number of apple and cheese candies in Packet J.

	Packet J		Packet K
	Apple	Cheese	Apple	Cheese
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of candies in Packet J
= 4 u + 1 u
= 5 u

Total number of candies in Packet K
= 2 x 5 u 
= 10 u

Number of apple candies in Packet K
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of apple candies in Packet K
= 10 u - 5.2 u
= 4.8 u

Number of cheese candies to be transferred from Packet K to Packet J
= 4 u - 1 u
= 3 u

Percentage of candies to be transferred from Packet K
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%