60% of the sweets in Packet G were cherry sweets and the rest were vanilla sweets. Packet H had 25% more cherry sweets than Packet G and twice as many sweets than the total number of sweets in Packet G. Find the percentage of the vanilla sweets in Packet H that would need to be transferred into Packet G, so that there were an equal number of cherry and vanilla sweets in Packet G.

	Packet G		Packet H
	Cherry	Vanilla	Cherry	Vanilla
	5 u		10 u
Before	3 u	2 u	3.75 u	6.25 u
Change		+ 1 u		- 1 u
After	3 u	3 u	3.75 u	5.25 u

60% = ⁶⁰₁₀₀ = ³₅
100 %+ 25% = 125%

 Total number of sweets in Packet G
= 3 u + 2 u
= 5 u

Total number of sweets in Packet H
= 2 x 5 u 
= 10 u

Number of cherry sweets in Packet H
= 125% x 3 u
=  ¹²⁵₁₀₀ x 3 u
= 3.75 u

Number of cherry sweets in Packet H
= 10 u - 3.75 u
= 6.25 u

Number of vanilla sweets to be transferred from Packet H to Packet G
= 3 u - 2 u
= 1 u

Percentage of sweets to be transferred from Packet H
= ¹_6.25 x 100%
= 16%

Answer(s): 16%