60% of the mini cupcakes in Packet Y were cheese mini cupcakes and the rest were blueberry mini cupcakes. Packet Z had 25% more cheese mini cupcakes than Packet Y and twice as many mini cupcakes than the total number of mini cupcakes in Packet Y. Find the percentage of the blueberry mini cupcakes in Packet Z that would need to be transferred into Packet Y, so that there were an equal number of cheese and blueberry mini cupcakes in Packet Y.

	Packet Y		Packet Z
	Cheese	Blueberry	Cheese	Blueberry
	5 u		10 u
Before	3 u	2 u	3.75 u	6.25 u
Change		+ 1 u		- 1 u
After	3 u	3 u	3.75 u	5.25 u

60% = ⁶⁰₁₀₀ = ³₅
100 %+ 25% = 125%

 Total number of mini cupcakes in Packet Y
= 3 u + 2 u
= 5 u

Total number of mini cupcakes in Packet Z
= 2 x 5 u 
= 10 u

Number of cheese mini cupcakes in Packet Z
= 125% x 3 u
=  ¹²⁵₁₀₀ x 3 u
= 3.75 u

Number of cheese mini cupcakes in Packet Z
= 10 u - 3.75 u
= 6.25 u

Number of blueberry mini cupcakes to be transferred from Packet Z to Packet Y
= 3 u - 2 u
= 1 u

Percentage of mini cupcakes to be transferred from Packet Z
= ¹_6.25 x 100%
= 16%

Answer(s): 16%