80% of the sweets in Packet E were vanilla sweets and the rest were apple sweets. Packet F had 30% more vanilla sweets than Packet E and twice as many sweets than the total number of sweets in Packet E. Find the percentage of the apple sweets in Packet F that would need to be transferred into Packet E, so that there were an equal number of vanilla and apple sweets in Packet E.

	Packet E		Packet F
	Vanilla	Apple	Vanilla	Apple
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of sweets in Packet E
= 4 u + 1 u
= 5 u

Total number of sweets in Packet F
= 2 x 5 u 
= 10 u

Number of vanilla sweets in Packet F
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of vanilla sweets in Packet F
= 10 u - 5.2 u
= 4.8 u

Number of apple sweets to be transferred from Packet F to Packet E
= 4 u - 1 u
= 3 u

Percentage of sweets to be transferred from Packet F
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%