80% of the candies in Packet X were cheese candies and the rest were strawberry candies. Packet Y had 30% more cheese candies than Packet X and twice as many candies than the total number of candies in Packet X. Find the percentage of the strawberry candies in Packet Y that would need to be transferred into Packet X, so that there were an equal number of cheese and strawberry candies in Packet X.

	Packet X		Packet Y
	Cheese	Strawberry	Cheese	Strawberry
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of candies in Packet X
= 4 u + 1 u
= 5 u

Total number of candies in Packet Y
= 2 x 5 u 
= 10 u

Number of cheese candies in Packet Y
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of cheese candies in Packet Y
= 10 u - 5.2 u
= 4.8 u

Number of strawberry candies to be transferred from Packet Y to Packet X
= 4 u - 1 u
= 3 u

Percentage of candies to be transferred from Packet Y
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%