70% of the lollipops in Packet L were chocolate chip lollipops and the rest were cheese lollipops. Packet M had 25% more chocolate chip lollipops than Packet L and four times as many lollipops than the total number of lollipops in Packet L. Find the percentage of the cheese lollipops in Packet M that would need to be transferred into Packet L, so that there were an equal number of chocolate chip and cheese lollipops in Packet L.
|
Packet L |
Packet M |
|
Chocolate Chip |
Cheese |
Chocolate Chip |
Cheese |
|
10 u |
40 u |
Before |
7 u |
3 u |
8.75 u |
31.25 u |
Change |
|
+ 4 u |
|
- 4 u |
After |
7 u |
7 u |
8.75 u |
27.25 u |
70% =
70100 =
710 100 %+ 25% = 125%
Total number of lollipops in Packet L
= 7 u + 3 u
= 10 u
Total number of lollipops in Packet M
= 4 x 10 u
= 40 u
Number of chocolate chip lollipops in Packet M
= 125% x 7 u
=
125100 x 7 u
= 8.75 u
Number of chocolate chip lollipops in Packet M
= 40 u - 8.75 u
= 31.25 u
Number of cheese lollipops to be transferred from Packet M to Packet L
= 7 u - 3 u
= 4 u
Percentage of lollipops to be transferred from Packet M
=
431.25 x 100%
= 12.8%
Answer(s): 12.8%