60% of the mochi balls in Packet K were cheese mochi balls and the rest were apple mochi balls. Packet L had 25% more cheese mochi balls than Packet K and twice as many mochi balls than the total number of mochi balls in Packet K. Find the percentage of the apple mochi balls in Packet L that would need to be transferred into Packet K, so that there were an equal number of cheese and apple mochi balls in Packet K.
|
Packet K |
Packet L |
|
Cheese |
Apple |
Cheese |
Apple |
|
5 u |
10 u |
Before |
3 u |
2 u |
3.75 u |
6.25 u |
Change |
|
+ 1 u |
|
- 1 u |
After |
3 u |
3 u |
3.75 u |
5.25 u |
60% =
60100 =
35 100 %+ 25% = 125%
Total number of mochi balls in Packet K
= 3 u + 2 u
= 5 u
Total number of mochi balls in Packet L
= 2 x 5 u
= 10 u
Number of cheese mochi balls in Packet L
= 125% x 3 u
=
125100 x 3 u
= 3.75 u
Number of cheese mochi balls in Packet L
= 10 u - 3.75 u
= 6.25 u
Number of apple mochi balls to be transferred from Packet L to Packet K
= 3 u - 2 u
= 1 u
Percentage of mochi balls to be transferred from Packet L
=
16.25 x 100%
= 16%
Answer(s): 16%