70% of the lollipops in Packet E were cherry lollipops and the rest were banana lollipops. Packet F had 25% more cherry lollipops than Packet E and four times as many lollipops than the total number of lollipops in Packet E. Find the percentage of the banana lollipops in Packet F that would need to be transferred into Packet E, so that there were an equal number of cherry and banana lollipops in Packet E.
|
Packet E |
Packet F |
|
Cherry |
Banana |
Cherry |
Banana |
|
10 u |
40 u |
Before |
7 u |
3 u |
8.75 u |
31.25 u |
Change |
|
+ 4 u |
|
- 4 u |
After |
7 u |
7 u |
8.75 u |
27.25 u |
70% =
70100 =
710 100 %+ 25% = 125%
Total number of lollipops in Packet E
= 7 u + 3 u
= 10 u
Total number of lollipops in Packet F
= 4 x 10 u
= 40 u
Number of cherry lollipops in Packet F
= 125% x 7 u
=
125100 x 7 u
= 8.75 u
Number of cherry lollipops in Packet F
= 40 u - 8.75 u
= 31.25 u
Number of banana lollipops to be transferred from Packet F to Packet E
= 7 u - 3 u
= 4 u
Percentage of lollipops to be transferred from Packet F
=
431.25 x 100%
= 12.8%
Answer(s): 12.8%