70% of the caramel apples in Packet J were chocolate chip caramel apples and the rest were blueberry caramel apples. Packet K had 25% more chocolate chip caramel apples than Packet J and four times as many caramel apples than the total number of caramel apples in Packet J. Find the percentage of the blueberry caramel apples in Packet K that would need to be transferred into Packet J, so that there were an equal number of chocolate chip and blueberry caramel apples in Packet J.
|
Packet J |
Packet K |
|
Chocolate Chip |
Blueberry |
Chocolate Chip |
Blueberry |
|
10 u |
40 u |
Before |
7 u |
3 u |
8.75 u |
31.25 u |
Change |
|
+ 4 u |
|
- 4 u |
After |
7 u |
7 u |
8.75 u |
27.25 u |
70% =
70100 =
710 100 %+ 25% = 125%
Total number of caramel apples in Packet J
= 7 u + 3 u
= 10 u
Total number of caramel apples in Packet K
= 4 x 10 u
= 40 u
Number of chocolate chip caramel apples in Packet K
= 125% x 7 u
=
125100 x 7 u
= 8.75 u
Number of chocolate chip caramel apples in Packet K
= 40 u - 8.75 u
= 31.25 u
Number of blueberry caramel apples to be transferred from Packet K to Packet J
= 7 u - 3 u
= 4 u
Percentage of caramel apples to be transferred from Packet K
=
431.25 x 100%
= 12.8%
Answer(s): 12.8%