80% of the lollipops in Packet A were strawberry lollipops and the rest were cranberry lollipops. Packet B had 30% more strawberry lollipops than Packet A and twice as many lollipops than the total number of lollipops in Packet A. Find the percentage of the cranberry lollipops in Packet B that would need to be transferred into Packet A, so that there were an equal number of strawberry and cranberry lollipops in Packet A.

	Packet A		Packet B
	Strawberry	Cranberry	Strawberry	Cranberry
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of lollipops in Packet A
= 4 u + 1 u
= 5 u

Total number of lollipops in Packet B
= 2 x 5 u 
= 10 u

Number of strawberry lollipops in Packet B
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of strawberry lollipops in Packet B
= 10 u - 5.2 u
= 4.8 u

Number of cranberry lollipops to be transferred from Packet B to Packet A
= 4 u - 1 u
= 3 u

Percentage of lollipops to be transferred from Packet B
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%