80% of the caramel apples in Packet H were banana caramel apples and the rest were apple caramel apples. Packet J had 30% more banana caramel apples than Packet H and twice as many caramel apples than the total number of caramel apples in Packet H. Find the percentage of the apple caramel apples in Packet J that would need to be transferred into Packet H, so that there were an equal number of banana and apple caramel apples in Packet H.

	Packet H		Packet J
	Banana	Apple	Banana	Apple
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of caramel apples in Packet H
= 4 u + 1 u
= 5 u

Total number of caramel apples in Packet J
= 2 x 5 u 
= 10 u

Number of banana caramel apples in Packet J
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of banana caramel apples in Packet J
= 10 u - 5.2 u
= 4.8 u

Number of apple caramel apples to be transferred from Packet J to Packet H
= 4 u - 1 u
= 3 u

Percentage of caramel apples to be transferred from Packet J
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%