80% of the sweets in Packet G were apple sweets and the rest were apricot sweets. Packet H had 30% more apple sweets than Packet G and twice as many sweets than the total number of sweets in Packet G. Find the percentage of the apricot sweets in Packet H that would need to be transferred into Packet G, so that there were an equal number of apple and apricot sweets in Packet G.

	Packet G		Packet H
	Apple	Apricot	Apple	Apricot
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of sweets in Packet G
= 4 u + 1 u
= 5 u

Total number of sweets in Packet H
= 2 x 5 u 
= 10 u

Number of apple sweets in Packet H
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of apple sweets in Packet H
= 10 u - 5.2 u
= 4.8 u

Number of apricot sweets to be transferred from Packet H to Packet G
= 4 u - 1 u
= 3 u

Percentage of sweets to be transferred from Packet H
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%