80% of the lollipops in Packet V were cranberry lollipops and the rest were apple lollipops. Packet W had 30% more cranberry lollipops than Packet V and twice as many lollipops than the total number of lollipops in Packet V. Find the percentage of the apple lollipops in Packet W that would need to be transferred into Packet V, so that there were an equal number of cranberry and apple lollipops in Packet V.

	Packet V		Packet W
	Cranberry	Apple	Cranberry	Apple
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of lollipops in Packet V
= 4 u + 1 u
= 5 u

Total number of lollipops in Packet W
= 2 x 5 u 
= 10 u

Number of cranberry lollipops in Packet W
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of cranberry lollipops in Packet W
= 10 u - 5.2 u
= 4.8 u

Number of apple lollipops to be transferred from Packet W to Packet V
= 4 u - 1 u
= 3 u

Percentage of lollipops to be transferred from Packet W
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%