80% of the lollipops in Packet T were vanilla lollipops and the rest were chocolate chip lollipops. Packet U had 30% more vanilla lollipops than Packet T and twice as many lollipops than the total number of lollipops in Packet T. Find the percentage of the chocolate chip lollipops in Packet U that would need to be transferred into Packet T, so that there were an equal number of vanilla and chocolate chip lollipops in Packet T.
|
Packet T |
Packet U |
|
Vanilla |
Chocolate Chip |
Vanilla |
Chocolate Chip |
|
5 u |
10 u |
Before |
4 u |
1 u |
5.2 u |
4.8 u |
Change |
|
+ 3 u |
|
- 3 u |
After |
4 u |
4 u |
5.2 u |
1.8 u |
80% =
80100 =
45 100 %+ 30% = 130%
Total number of lollipops in Packet T
= 4 u + 1 u
= 5 u
Total number of lollipops in Packet U
= 2 x 5 u
= 10 u
Number of vanilla lollipops in Packet U
= 130% x 4 u
=
130100 x 4 u
= 5.2 u
Number of vanilla lollipops in Packet U
= 10 u - 5.2 u
= 4.8 u
Number of chocolate chip lollipops to be transferred from Packet U to Packet T
= 4 u - 1 u
= 3 u
Percentage of lollipops to be transferred from Packet U
=
34.8 x 100%
= 62.5%
Answer(s): 62.5%