80% of the caramel apples in Packet S were strawberry caramel apples and the rest were banana caramel apples. Packet T had 30% more strawberry caramel apples than Packet S and twice as many caramel apples than the total number of caramel apples in Packet S. Find the percentage of the banana caramel apples in Packet T that would need to be transferred into Packet S, so that there were an equal number of strawberry and banana caramel apples in Packet S.

	Packet S		Packet T
	Strawberry	Banana	Strawberry	Banana
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of caramel apples in Packet S
= 4 u + 1 u
= 5 u

Total number of caramel apples in Packet T
= 2 x 5 u 
= 10 u

Number of strawberry caramel apples in Packet T
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of strawberry caramel apples in Packet T
= 10 u - 5.2 u
= 4.8 u

Number of banana caramel apples to be transferred from Packet T to Packet S
= 4 u - 1 u
= 3 u

Percentage of caramel apples to be transferred from Packet T
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%