80% of the lollipops in Packet X were strawberry lollipops and the rest were chocolate chip lollipops. Packet Y had 30% more strawberry lollipops than Packet X and twice as many lollipops than the total number of lollipops in Packet X. Find the percentage of the chocolate chip lollipops in Packet Y that would need to be transferred into Packet X, so that there were an equal number of strawberry and chocolate chip lollipops in Packet X.

	Packet X		Packet Y
	Strawberry	Chocolate Chip	Strawberry	Chocolate Chip
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of lollipops in Packet X
= 4 u + 1 u
= 5 u

Total number of lollipops in Packet Y
= 2 x 5 u 
= 10 u

Number of strawberry lollipops in Packet Y
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of strawberry lollipops in Packet Y
= 10 u - 5.2 u
= 4.8 u

Number of chocolate chip lollipops to be transferred from Packet Y to Packet X
= 4 u - 1 u
= 3 u

Percentage of lollipops to be transferred from Packet Y
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%